A projectile is shot from the ground at a velocity of 3 m/s and at an angle of (7pi)/12. How long will it take for the projectile to land?

Jul 7, 2016

$0.0196 s$

Explanation:

The equation to find time of flight given angle and speed of launch is:
$t = \frac{2 {v}_{o} \sin \left(\theta\right)}{g}$
where:
$t$ is the time taken to hit the ground
${v}_{o}$ is the launch speed of the projectile (3ms^-1)
$\theta$ is the angle of launch ($\frac{7 \pi}{12}$)
$g$ is the acceleration due to gravity ($9.81 m {s}^{-} 1$)

We then substitute these values into the equation

t=(2(3ms^-1)sin((7pi)/12))/(9.81ms^-1`)

t=0.01955s = 0.0196s" (3 s.f.")

For more projectile motion formulas look here.