A projectile is shot from the ground at a velocity of 3 m/s at an angle of pi/4. How long will it take for the projectile to land?

Dec 1, 2017

$\text{0.432 s}$

Explanation:

v = "3 m/s" = sqrt((v_h)² + (v_v)²)

$\text{Angle" = 45^@ => v_"horiz" = v_"vertik} = \frac{3}{\sqrt{2}}$

Since

$v = g t \implies t = \frac{v}{g} = \frac{3}{\sqrt{2} \cdot g}$

$t =$ time to fall, here we have the double of that: rise & fall

$\implies T = \frac{6}{\sqrt{2} \cdot g} = \text{0.432 s}$