# A sample of gas occupies 21 L under a pressure of 1.3 atm. What would the resulting volume be if the pressure were increased to 3.9 atm if the temperature did not change?

Jul 5, 2017

The volume is $= 7 L$

#### Explanation:

We apply Boyle's Law

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

The initial volume is $V - 1 = 21 L$

The initial pressure is ${P}_{1} = 1.3 a t m$

The final pressure is ${P}_{2} = 3.9 a t m$

The final volume is

${V}_{2} = {P}_{1} / {P}_{2} \cdot {V}_{1} = \frac{1.3}{3.9} \cdot 21$

$= 7 L$