# A sample of ideal gas has a volume of 325 L at 13.60*C and 1.60 atm. What is the volume of the gas at 23.60°C and .994 atm?

May 8, 2017

${V}_{2} = 541 \cdot L$

#### Explanation:

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

And so we solve for ${V}_{2} = \frac{{P}_{1} {T}_{2} {V}_{1}}{{P}_{2} {T}_{1}}$

$= \frac{1.60 \cdot a t m \times 296.75 \cdot K \times 325 \cdot L}{0.994 \cdot a t m \times 286.8 \cdot K}$

$= 541 \cdot L$.

Is my right arithmetic right? All care taken, but no responsibility accepted. Is it reasonable that the volume has increased so markedly? Why or why not?