A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $66$ $66$ and the height of the cylinder is $5$ $5$ . If the volume of the solid is $27 π$ $27 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2016-06-02T06:16:12

Area of the base is $π = 3.1416$ $pi=3.1416$

Let the area of the base of cylinder be $A$ $A$ .

Hence volume of cylinder is $A \times 5 = 5 A$ $Axx5=5A$

and volume of cone is $\frac{1}{3} \times A \times 66 = 22 A$ $1/3xxAxx66=22A$

Hence total volume is $22 A + 5 A = 27 A = 27 π$ $22A+5A=27A=27pi$

Therefore $A = \frac{27 π}{27} = π = 3.1416$ $A=(27pi)/27=pi=3.1416$

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 6666 and the height of the cylinder is 55 . If the volume of the solid is 27π27 pi, what is the area of the base of the cylinder?