A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #12 # and the height of the cylinder is #28 #. If the volume of the solid is #16 pi#, what is the area of the base of the cylinder?

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Answer 1 · 2016-06-07T13:24:39

Area of base of cylinder is #pi/2#.

Let the area of the base of cylinder be #A#, as its height is #28# units

volume of cylinder is #28xxA=28A#

volume of cone of height #12# units will be #1/3xxAxx12=4A# units

hence total volume is #28A+4A=32A=16pi#

Hence, Area of base of cylinder is #16pi/32=pi/2#.