A solid disk with a radius of #2 m# and mass of #2 kg# is rotating on a frictionless surface. If #32 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #1 Hz#?

1 Answer
Apr 30, 2017

Answer:

The torque is #=5.09Nm#

Explanation:

Mass of disc #=2kg#

Radius of disc #=2m#

The power is related to the torque by the equation

#P=tau *omega#

#P=32W#

Frequency of rotation is #f=1Hz#

#omega=f*2pi#

angular velocity, #omega=1*2pi rads^-1#

torque, #tau=P/omega#

#=32/(2pi)=5.09Nm#