A solid disk with a radius of #24 m# and mass of #6 kg# is rotating on a frictionless surface. If #480 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #3 Hz#?

1 Answer
Mar 3, 2017

Answer:

The torque is #=25.5Nm#

Explanation:

mass of disc #=6kg#

radius of disc #=24m#

The power is related to the torque by the equation

#P=tau *omega#

#P=480W#

angular velocity, #omega=3*2pi rads^-1#

torque, #tau=P/omega#

#=480/(6pi)=25.5Nm#