A solid disk with a radius of #3 m# and mass of #4 kg# is rotating on a frictionless surface. If #120 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #8 Hz#?
The torque applied is 2.38 N-m.
This goes very simple, Power is the product of the torque and angular velocity, similar to
So here angular acceleration comes with
Calculating the angular velocity with given frequency we get,
Now the above power equation becomes
Substituting the given values we get,