A solid disk with a radius of #4 m# and mass of #6 kg# is rotating on a frictionless surface. If #960 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #5 Hz#?

Question

1215 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-26T12:03:16

The torque is #=30.6Nm#

Mass of disc #=6kg#

Radius of disc #=4m#

The power is related to the torque by the equation

#P=tau *omega#

#P=960W#

Frequency of rotation is #f=5Hz#

#omega=f*2pi#

angular velocity, #omega=5*2pi rads^-1#

torque, #tau=P/omega#

#=960/(10pi)=30.6Nm#