A solid disk with a radius of #6 m# and mass of #2 kg# is rotating on a frictionless surface. If #3 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #4 Hz#?

1 Answer
Nov 16, 2017

Answer:

The torque is #=0.12Nm#

Explanation:

Apply the equation

#P=tau omega#

The power is #P=3W#

The frequency is #f=4Hz#

The angular velocity is

#omega=2pif=2xxpixx4=(8pi)rads^-1#

Therefore,

The torque is

#tau=P/omega=3/(8pi)=0.12Nm#