A solid disk with a radius of #6 m# and mass of #9 kg# is rotating on a frictionless surface. If #750 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #4 Hz#?

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Answer 1 · 2017-02-24T19:02:54

The torque is #=119.4Nm#

The power is related to the torque, by the equation

#P=tau omega#

#P=# power

#tau=# torque

#omega=# angular velocity

#P=750W#

#omega=4*2pi=(8pi)rads^-1#

# tau = 750/(2pi) =119.4Nm#