A solid disk with a radius of #8# #m# and mass of #2# #kg# is rotating on a frictionless surface. If #640# #W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #16# #Hz#?

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Answer 1 · 2017-03-28T12:23:01

The torque is #=6.4Nm#

mass of disc #=2kg#

radius of disc #=8m#

The power is related to the torque by the equation

#P=tau *omega#

#P=640W#

Frequency of rotation is #f=16Hz#

#omega=f*2pi#

angular velocity, #omega=16*2pi rads^-1#

torque, #tau=P/omega#

#=640/(32pi)=6.4Nm#