A solid disk with a radius of #9 m# and mass of #2 kg# is rotating on a frictionless surface. If #480 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #15 Hz#?

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Answer 1 · 2017-02-25T09:23:44

The torque is #=5.1Nm#

The power is related to the torque, by the equation

#P=tau omega#

#P=# power

#tau=# torque

#omega=# angular velocity

#P=480W#

#omega=15*2pi=(30pi)rads^-1#

# tau = 480/(30pi) =5.1Nm#