Question

A squash player hits the ball 2.3m to the side wall. The ball rebounds at an angle of 100 degrees and travels 3.1m to the front wall. How far is the ball from the player when it hits the front wall?

Answer 1

Use the law of cosines.

Explanation:

The law of cosines is:

`c^2=a^2+b^2-2abcos(C^o)`

`c^2=2.3^2+3.1^2-2(2.3)(3.1)cos(100^o)`

`c=4.168`

hope that helped