A triangle has sides A,B, and C. If the angle between sides A and B is (pi)/8, the angle between sides B and C is pi/4, and the length of B is 1, what is the area of the triangle?

(sqrt2 $-$ 1) / (2sqrt2).
Angle between B and C is 5$\pi$/8 .
Use sides are proportional to sines of opposite angles and area to find C = tan $\pi$/8.
Area = 1/2 B.C. sin $\pi$4.= sin$\pi$/8 .sin$\pi$/8 = ( 1 $-$ cos $\pi$/4)/2