A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 1, respectively. The angle between A and C is #(13pi)/24# and the angle between B and C is # (3pi)/8#. What is the area of the triangle?

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Answer 1 · 2017-03-05T09:33:27

the area is #(sqrt6-sqrt2)/4#

The angle between A and B is:

#hat(AB)=pi-13/24pi-3/8pi=2/24pi=1/12pi#

The area of the triangle is:

#1/2A*B*sin(hat(AB))=1/cancel2*cancel2*1*sin(pi/12)#

#(sqrt6-sqrt2)/4#