# A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 4, respectively. The angle between A and C is (13pi)/24 and the angle between B and C is  (3pi)/8. What is the area of the triangle?

4 sin $\pi$/12 = 1.0353 areal units, nearly.
The third angle = $\pi$ $-$ 13$\pi$/24 + 3$\pi$/8) = $\pi$/12.
The altitude on the side A is B sin $\pi$/12.
Area = base X altitude)/2 = (2 X 4 sin $\pi$/12) / 2