# A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 4, respectively. The angle between A and C is (5pi)/24 and the angle between B and C is  (5pi)/24. What is the area of the triangle?

Jul 7, 2018

The triangle is not feasible.

#### Explanation:

The length of sides $A \mathmr{and} B$ are $3 , 4$ unit respectively.

Angle between Sides $A \mathmr{and} C$ is $\angle b = \frac{5 \pi}{24} = = \frac{5 \cdot 180}{24} = \frac{900}{24} = {37.5}^{0}$

Angle between Sides $B \mathmr{and} C$ is $\angle a = \frac{5 \pi}{24} = = \frac{5 \cdot 180}{24} = \frac{900}{24} = {37.5}^{0}$

Since $\angle b \mathmr{and} \angle a$ are equal , the triangle must be isosceles of

which opposite sides $B \mathmr{and} A$ should be of equal length.

Here B !=A ;(4 !=3) Therefore the triangle is not possible. [Ans]