# A triangle has sides A, B, and C. Sides A and B have lengths of 8 and 10, respectively. The angle between A and C is (3pi)/24 and the angle between B and C is  (5pi)/24. What is the area of the triangle?

$a = 8 , b = 10 , \hat{A} = \frac{5 \pi}{24} , \hat{B} = \frac{3 \pi}{24}$
We know greater side will have greater angle opposite to it. But in the given sum, though $\left(a = 8\right) < \left(b = 10\right) , \hat{A} = \frac{5 \pi}{24}$, which is greater than $\hat{B}$.