A triangle has sides A, B, and C. The angle between sides A and B is #(5pi)/12# and the angle between sides B and C is #pi/12#. If side B has a length of 48, what is the area of the triangle?

1 Answer
Jan 28, 2016

Answer:

4299.322531

Explanation:

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lets draw a perpendicular line on B .
suppose, the length of the perpendicular is D
now, the problem says, the angle between A and B is #(5pi)/12#
now,
in, #triangleABD#,
#D/B=tan((5pi)/12)#
#or,D=Btan((5pi)/12)#
now, by putting the values, B=48 and tan#(5pi)/12# ,
#D=48*3.732050808#
#or, D=179.1384388#
so,
The area of #triangleABC=1/2*B*D#
now, by putting the value of B and D in the above equation, we get,
#triangleABC=1/2*48*179.1384388=4299.322531#