A triangle has sides A, B, and C. The angle between sides A and B is #(5pi)/12# and the angle between sides B and C is #pi/12#. If side B has a length of 10, what is the area of the triangle?

1 Answer
Binayaka C.
May 4, 2016

Hence Area of the right angled triangle is #12.5# square units.

Explanation:

The angle between sides A and B is #/_C=5*180/12=75^0#
The angle between sides B and C is #/_A=180/12=15^0 :. /_B=180-(75+15)=90^0# Side #B = 10# Applying sine law #A/sinA=B/sinB=C/sinC#
we get #A= 10*sin15=2.588# and #C= 10*sin75=9.659# Hence Area of the right angled triangle is #= 1/2*9.659*2.588=12.5# Square units.
Here, Base #= 9.659# and Height #=2.588#[Ans]

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