Question

A triangle has sides A, B, and C. The angle between sides A and B is `(5pi)/12` and the angle between sides B and C is `pi/12`. If side B has a length of 11, what is the area of the triangle?

Answer 1

The area is given by `A=121/2*((1+sqrt(3))/(2*sqrt(2)))^2`

Explanation:

The third angle is
`pi/2`
So we have
`A=1/2ac`
and from

`sin(pi/12)=a/11`
`sin(5*pi/12)=c/11`
and
`sin(pi/12)=sin(5pi/12)=(1+sqrt(3))/(2*sqrt(2))`