Question

A triangle has sides A, B, and C. The angle between sides A and B is `(pi)/2` and the angle between sides B and C is `pi/12`. If side B has a length of 2, what is the area of the triangle?

Answer 1

0.53589838486
I do not have my scientific calculator with me, so my answer could be wrong. However, these are the steps to solve them

Explanation:

The angle between A and C:
-The sum of an angle is `Pi`

`Pi-Pi/2-Pi/12=5Pi/12`

Find either side of A/C using the sine rule:
What is sine rule> http://www.bbc.co.uk/schools/gcsebitesize/maths/geometry/furthertrigonometryhirev1.shtml

For A;
`A/sin(Pi/12)=2/sin(5Pi/12)`
`A=(2* sin(Pi/12))/sin(5Pi/12)`
`A=0.53589838486`

. Using the `1/2(A)(B)sinC` What is the formula for area of triangle (http://www.bbc.co.uk/schools/gcsebitesize/maths/geometry/furthertrigonometryhirev3.shtml) to find the area.

`1/2(0.53589838486)(2)sin(Pi/2)=0.53589838486`