A triangle has sides A, B, and C. The angle between sides A and B is $(pi)/2$ and the angle between sides B and C is $pi/12$ . If side B has a length of 25, what is the area of the triangle?

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Answer 1 · 2018-03-16T03:56:55

Area of the triangle $~~ 83.73$ sq units

$hatC = pi / 2, hat A = pi / 12, hat B = pi - pi / 12 - pi / 2 = (5pi) / 12, b = 25$

It's a right triangle.

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$a / sin (pi/12) = c / sin (pi/2) = 25 / sin ((5pi)/12)$

$a = (25 * Sin (pi/12) ) / sin((5pi)/12) ~~ 6.7$

$Area = (1/2) a * b = (25 * 6.7) / 2 ~~ 83.73$

since it's a right triangle with $hatC = pi/2$

A triangle has sides A, B, and C. The angle between sides A and B is (pi)/2(pi)/2 and the angle between sides B and C is pi/12pi/12. If side B has a length of 25, what is the area of the triangle?