# A triangle has sides A, B, and C. The angle between sides A and B is (pi)/3 and the angle between sides B and C is pi/6. If side B has a length of 26, what is the area of the triangle?

$\frac{169 \sqrt{3}}{2}$
The third angle $\frac{\pi}{2}$, which means it is a right angled triangle.
The three sides are $1 : \sqrt{3} : 2$ in length with side B being the longest. Side A is vertical to side C. Side A=$13$, side C=$13 \sqrt{3}$
Area of triangle=$\frac{1}{2} \cdot 13 \cdot 13 \sqrt{3} = \frac{169 \sqrt{3}}{2}$