A triangle has sides A, B, and C. The angle between sides A and B is (pi)/3. If side C has a length of 15 and the angle between sides B and C is ( 3 pi)/8, what are the lengths of sides A and B?

1 Answer

side a=16.0021
side b=13.7413

Explanation:

To solve the triangle use the Sine Law
a/sin A=b/sin B=c/sin C

Compute angle B first using the formula A+B+C=pi

B=pi-A-C

B=pi-(3pi)/8-pi/3

B=(7pi)/24

Compute side a:

a/sin A=c/sin C

a=(c*sin A)/sin C=15*sin ((3pi)/8)/(sin (pi/3))

a=16.0021

Compute side b:

b/sin B=c/sin C

b=(c*sin B)/sin C=15*sin ((7pi)/24)/(sin (pi/3))

b=13.7413