A triangle has sides A, B, and C. The angle between sides A and B is (pi)/3. If side C has a length of 16 and the angle between sides B and C is ( 3 pi)/8, what are the lengths of sides A and B?

1 Answer
Mar 26, 2018

color(green)("length of side " a) = (c * sin A) / sin C = color(green)(17.07)

color(green)("Length of side " b) = (c * sin B) / sin C = color(green)(2.41)

Explanation:

"Given : " hat C = pi/3, c = 16, hat A = (3pi) / 8

"To find lengths of sides a & b"

http://www.dummies.com/education/math/trigonometry/laws-of-sines-and-cosines/http://www.dummies.com/education/math/trigonometry/laws-of-sines-and-cosines/

hat B = pi - pi/3 - (5pi)/8 = pi/24

Applying Law of sines,

a / sin A = b / sin B = c / sin C

color(green)(a) = (c * sin A) / sin C = (16 * sin ((3pi)/8)) / sin(pi/3) = color(green)(17.07)

color(green)(b) = (c * sin B) / sin C = (16 * sin (pi/24)) / sin(pi/3) = color(green)(2.41)