A triangle has sides A, B, and C. The angle between sides A and B is (pi)/3. If side C has a length of 18 and the angle between sides B and C is ( pi)/8, what are the lengths of sides A and B?

1 Answer
Oct 13, 2016

abs(A)~~7.95
abs(B)~~20.61

Explanation:

Given:
color(white)("XXX")/_A:B = pi/3
color(white)("XXX")/_B:C=pi/8
color(white)("XXX")abs(C)=18

/_A:B=pi/3 and /_B:C=pi/8color(white)("X")
color(white)("XXX")rarrcolor(white)("X")/_C:A = pi-(pi/3+pi/8) = (13pi)/24

By the Law of Sines
color(white)("XXX")abs(A)/sin(/_B:C) = abs(B)/sin(/_C:A)=abs(C)/sin(/_A:B)

abs(C)/sin(/_A:B) = 18/sin(pi/3) = 20.78461

abs(A)=20.78461 xx sin(/_B:C) = 20.78461 xx sin(pi/8) =7.953926

abs(B)=20.78461xxsin(/_C:A)=20.78461xxxin((13pi)/24) =20.60679