A triangle has sides A, B, and C. The angle between sides A and B is (pi)/4. If side C has a length of 25 and the angle between sides B and C is ( 3 pi)/8, what are the lengths of sides A and B?

1 Answer
Apr 11, 2018

color(indigo)("Length of side " = a = b = 6.53 " units"

Explanation:

hat A = (3pi)/8, hat C = pi/4, c = 25, " To find a & b"

hat B = pi - (3pi)/8 - pi / 4 = (3pi) / 8

It's an isosceles triangle with sides a & b equal.

According to the law of sines,

a / sin A = b / sin B = c / sin C

:. a = b = (c * sin B) / sin C = (25 * sin ((3pi)/8)) / sin (pi/4)

color(indigo)(a = b = 6.53 " units"