A triangle has two corners with angles of # (2 pi ) / 3 # and # ( pi )/ 4 #. If one side of the triangle has a length of #1 #, what is the largest possible area of the triangle?

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Answer 1 · 2017-12-08T13:57:49

Largest possible area of the triangle is 2.3458

Given are the two angles #(2pi)/3# and #pi/4# and the length 1

The remaining angle:

#= pi - (((2pi)/3) + pi/4) = pi/12#

I am assuming that length AB (1) is opposite the smallest angle.

Using the ASA

Area#=(c^2*sin(A)*sin(B))/(2*sin(C)#

Area#=( 1^2*sin(pi/4)*sin((2pi)/3))/(2*sin(pi/12)#

Area#=2.3458#