A triangle has two corners with angles of # (2 pi ) / 3 # and # ( pi )/ 6 #. If one side of the triangle has a length of #3 #, what is the largest possible area of the triangle?

Question

1035 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-08T13:29:53

Largest possible area of the triangle is 3.8971

Given are the two angles #(2pi)/3# and #pi/6# and the length 3

The remaining angle:

#= pi - (((2pi)/3) + pi/6) = pi/6#

I am assuming that length AB (3) is opposite the smallest angle.

Using the ASA

Area#=(c^2*sin(A)*sin(B))/(2*sin(C)#

Area#=( 3^2*sin(pi/6)*sin((2pi)/3))/(2*sin(pi/6))#

Area#=3.8971#