After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 milliliters of a new solution. How would this be prepared?
Here's what I got.
You know that you need
#(100.0color(red)(cancel(color(black)("mL"))))/(25.0color(red)(cancel(color(black)("mL")))) = 4#
You thus know that for every
The trick now is to realize that despite the fact that you'd need
#"100.0 mL " - " 25.0 mL" = "75.0 mL"#
of water to make this new solution, you should not add exactly
So, to prepare this solution, you should add