# Alkanes have the general molecular formula C_nH_(2n+2). Thus, when n= 1, the alkane is CH_4, when n = 2, the alkane is C_2H_6 etc. If an alkane has a molar mass between 140 and 150, what is the alkene?

Dec 1, 2016

The required alkane is a Decane $\left({C}_{10} {H}_{22}\right)$.

#### Explanation:

This is a simple calculation.
The general formula for alkanes is ${C}_{n} {H}_{2 n + 2}$.

So, an alkane having 10 carbon atoms will surely have 22 hydrogen atoms, according to the given formula.

So, the molar mass of decane is equal to:
$= \left(10 \times 12\right) + \left(22 \times 1\right)$ grams.
$= 142$ grams.

Now, 142 lies between 140 & 150.
So, the alkane is Decane.