# An empty graduated cylinder has a mass of 34.90 g. The cylinder is filled to the 9.40 mL mark with a liquid. The mass the cylinder with liquid is found to be 47.99 g. What is the density of the liquid?

Sep 28, 2016

$\rho >$ $1 \cdot g \cdot m {L}^{-} 1$.

#### Explanation:

$\text{Density}$ $=$ $\text{Mass"/"Volume}$ $=$ $\frac{47.99 \cdot g - 34.90 \cdot g}{9.40 \cdot m L}$ $=$ ??g*mL^-1.

Sep 28, 2016

The density is $\text{1.39 g/mL}$ rounded to three signicant figures.

#### Explanation:

Volume of liquid is $\text{9.40 mL}$

To determine mass, subtract the mass of the empty cylinder from the mass of the cylinder plus liquid.

$\text{47.99 g"-"34.90 g"="13.09 g}$

The mass of the liquid is $\text{13.09 g}$.

Density is mass per unit volume. The equation for density is

$\text{density"="mass"/"volume}$

$\text{In this question, volume is measured in milliliters, mL}$, $\text{and mass is measured in grams, g.}$

Substitute your known values into the density equation and solve.

$\text{density"=(13.09"g")/(9.40"mL")="1.39 g/mL}$ rounded to three significant figures