An object with a mass of #15 kg# is lying still on a surface and is compressing a horizontal spring by #5/6 m#. If the spring's constant is #15 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Mar 30, 2016

Answer:

#mu=0,085#

Explanation:

#F=u_k*Delta x#

#u_k=15 " "(kg)/s^2#

#Delta x=5/6 " "m#

#F=15*5/6=75/6=25/2" N"#

#F_f=mu* N"( Friction Force)"#
#mu:"coefficient of static friction"#
#N:"normal force to the contacting surfaces"#
#"we can write "N=m*g" (The Newton's third law)"#

#F=F_f#
#"m:15 kg"#
#25/2=mu*15*9,81#

#25=2*15*9,81* mu#

#25=294,3*mu#

#mu=25/(294,3)#

#mu=0,085#