An object with a mass of #2 kg# is revolving around a point at a distance of #4 m#. If the object is making revolutions at a frequency of #5 Hz#, what is the centripetal force acting on the object?

1 Answer
Feb 14, 2016

Answer:

#F=1600*pi^2N#

Explanation:

#"you can use the Newton's second law"#
#F=m*a#
#"change linear acceleration to rotary acceleration"#
#a=v^2/r ; v=omega*r ; v^2=omega^2*r^2#
#a=omega^2*r#
#F=m*omega^2*r#
#F=m*(2*pi*f)^2*r#
#F=4*4*pi^2*25*4#
#F=4^3*5^2*pi^2#
#F=64*25*pi^2#
#F=1600*pi^2N#