An object with a mass of $2 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $5 Hz$ , what is the centripetal force acting on the object?

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An object with a mass of $2 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $5 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2016-02-14T18:53:06

$F=1600*pi^2N$

Explanation:

$"you can use the Newton's second law"$
$F=m*a$
$"change linear acceleration to rotary acceleration"$
$a=v^2/r ; v=omega*r ; v^2=omega^2*r^2$
$a=omega^2*r$
$F=m*omega^2*r$
$F=m*(2*pi*f)^2*r$
$F=4*4*pi^2*25*4$
$F=4^3*5^2*pi^2$
$F=64*25*pi^2$
$F=1600*pi^2N$

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An object with a mass of $2 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $5 Hz$ , what is the centripetal force acting on the object?

1 Answer

Explanation:

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An object with a mass of 2 kg2 kg is revolving around a point at a distance of 4 m4 m. If the object is making revolutions at a frequency of 5 Hz5 Hz, what is the centripetal force acting on the object?

1 Answer

Explanation:

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An object with a mass of $2 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $5 Hz$ , what is the centripetal force acting on the object?