An object with a mass of # 2 kg# is traveling in a circular path of a radius of #2 m#. If the object's angular speed changes from # 1 Hz# to # 2 Hz# in # 1 s#, what torque was applied to the object?

1 Answer
Mar 27, 2018

The torque was #=50.3Nm#

Explanation:

The torque is the rate of change of angular momentum

#tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt=Ialpha#

where #I# is the moment of inertia

For the object, #I=mr^2#

The mass is #m=2 kg#

The radius of the path is #r=2m#

So the moment of inertia is

,#I=2*(2)^2=8kgm^2#

The angular acceleration is

#alpha=(2pif_1-2pif_0)/t=(4-2)pi/1=2pirads^-2#

So,

The torque is

#tau=Ialpha=8*2pi=50.3m#