An object with a mass of # 2 kg# is traveling in a circular path of a radius of #4 m#. If the object's angular velocity changes from # 1 Hz# to # 3 Hz# in # 2 s#, what torque was applied to the object?

1 Answer
Feb 13, 2016

Answer:

#L=64pi#

Explanation:

#alpha=(Delta omega)/(Delta t)#
#"alpha is the angular acceleration for object"#
#alpha=(2pi*f_f-2pi*f_i)/2#
#alpha=(2pi*3-2pi*1)/2#
#alpha=4pi/2#
#alpha=2pi#
#"L:torque"#
#L=alpha*I#
#"I=m*r^2#
#L=2pi*2*4^2#
#L=64pi#