Question

An object with a mass of `2 kg` is traveling in a circular path of a radius of `4 m`. If the object's angular velocity changes from `1 Hz` to `3 Hz` in `2 s`, what torque was applied to the object?

Answer 1

`L=64pi`

Explanation:

`alpha=(Delta omega)/(Delta t)`
`"alpha is the angular acceleration for object"`
`alpha=(2pi*f_f-2pi*f_i)/2`
`alpha=(2pi*3-2pi*1)/2`
`alpha=4pi/2`
`alpha=2pi`
`"L:torque"`
`L=alpha*I`
`"I=m*r^2`
`L=2pi*2*4^2`
`L=64pi`