An object with a mass of $3 "kg"$ is traveling in a circular path of a radius of $2 "m"$ . If the object's angular velocity changes from $1 "Hz"$ to $18 "Hz"$ in $5 "s"$ , what torque was applied to the object?

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Answer 1 · 2016-01-20T11:46:08

Only the average torque can be calculated, which is $40.8 "Nm"$ .

The angular inpulse is given by

$mR^2Delta omega = (3"kg")(2"m")^2(18"Hz"-1"Hz")$

$= 204"kgm"^2"s"^{-1}$ .

If you are asked to find torque, you must assume that the angular acceleration is constant. In that case, the torque is given by

$frac{204"kgm"^2"s"^{-1}}{5"s"} = 40.8"Nm"$ .

An object with a mass of 3 "kg"3 "kg" is traveling in a circular path of a radius of 2 "m"2 "m". If the object's angular velocity changes from 1 "Hz"1 "Hz" to 18 "Hz"18 "Hz" in 5 "s" 5 "s", what torque was applied to the object?