# An object with a mass of  3 kg is traveling in a circular path of a radius of 6 m. If the object's angular velocity changes from  6 Hz to  14 Hz in 3 s, what torque was applied to the object?

Nov 11, 2017

$\text{1809.5 Nm}$
T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t
T = ("3 kg × (6 m)"^2 × 2 π (14 - 6) "Hz")/"3 s" = "1809.5 Nm"