Question

An object with a mass of `3 kg` is traveling in a circular path of a radius of `6 m`. If the object's angular velocity changes from `6 Hz` to `14 Hz` in `3 s`, what torque was applied to the object?

Answer 1

`"1809.5 Nm"`

Explanation:

Torque is rate of change of angular momentum.

`T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t`

`T = ("3 kg × (6 m)"^2 × 2 π (14 - 6) "Hz")/"3 s" = "1809.5 Nm"`