An object with a mass of  3 kg is traveling in a circular path of a radius of 6 m. If the object's angular velocity changes from  6 Hz to  17 Hz in 5 s, what torque was applied to the object?

Nov 11, 2017

$\text{1492.8 Nm}$ of Torque was applied to the object.

Explanation:

Torque is rate of change of angular momentum.

T = (I(omega_f - ω_i))/t

$= \frac{I 2 \pi \left({f}_{f} - {f}_{i}\right)}{t}$

$= \frac{m {r}^{2} 2 \pi \left({f}_{f} - {f}_{i}\right)}{t}$

= ("3 kg × (6 m)"^2 × 2 π (17 - 6) "Hz")/"5 s" = "1492.8 Nm"