An object with a mass of # 3 kg# is traveling in a circular path of a radius of #6 m#. If the object's angular velocity changes from # 6 Hz# to # 17 Hz# in #5 s#, what torque was applied to the object?
1 Answer
Nov 11, 2017
Explanation:
Torque is rate of change of angular momentum.
#= (I2pi(f_f - f_i))/t#
#= (mr^2 2pi(f_f - f_i))/t#
#= ("3 kg × (6 m)"^2 × 2 π (17 - 6) "Hz")/"5 s" = "1492.8 Nm"#