An object with a mass of # 3 kg# is traveling in a circular path of a radius of #7 m#. If the object's angular velocity changes from # 3 Hz# to # 9 Hz# in #3 s#, what torque was applied to the object?

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Answer 1 · 2016-03-25T22:45:10

#294 N*m#

The torque is the product between the inertial momentum and the angular acceleration #tau = I* alpha #.

As this case is single particle in a circular path #I =m*r^2# and

#omega = (Delta omega)/(Deltat)#, so

#tau= m*r*(Delta omega)/(Deltat) = 3kg*49m^2* (9Hz -3Hz)/(3sg) = 294 N*m#