# An object with a mass of 4 kg is revolving around a point at a distance of 2 m. If the object is making revolutions at a frequency of 5 Hz, what is the centripetal force acting on the object?

Jun 19, 2016

$= 7887.68 N$

#### Explanation:

Given

• $m \to \text{Mass of the object} = 4 k g$
• $r \to \text{Radius of circular path} = 2 m$
• $n \to \text{Frequency of revolution} = 5 H z$
• $w \to \text{Angular velocity} = 2 \pi n$

• We know centripetal force

• ${F}_{c} = m \times {w}^{2} \times r = = 4 {\pi}^{2} {n}^{2} \times m \times r$

$= 4 \cdot {3.14}^{2} \cdot {5}^{2} \cdot 4 \cdot 2 = 7887.68 N$