Question

An object with a mass of `5 kg` is on a surface with a kinetic friction coefficient of `3`. How much force is necessary to accelerate the object horizontally at `6 m/s^2`?

Answer 1

177 N

Explanation:

friction force is
`F_f= mu xx m xx g= 3 xx 5 kg xx 9,8 m/s^2= 147 N`
by the second dynamic principle
`F - F-f= m xx a`
F= 147 N + 5 kg xx 6 m/s^2= 177 N#