# An object with a mass of 5 kg is on a surface with a kinetic friction coefficient of  3 . How much force is necessary to accelerate the object horizontally at 6 m/s^2?

Jun 18, 2018

${F}_{f} = \mu \times m \times g = 3 \times 5 k g \times 9 , 8 \frac{m}{s} ^ 2 = 147 N$
$F - F - f = m \times a$