An object with a mass of 5 kg is revolving around a point at a distance of 3 m. If the object is making revolutions at a frequency of 1 Hz, what is the centripetal force acting on the object?

1 Answer
Jan 23, 2018

60π^2N

Explanation:

"Centripetal force" = (m*v^2)/r
The frequency was given as 1hz
Then "angular velocity" =2πf =(2π" rad")/s
Remember that "linear velocity" = "angular velocity"*"distance"
V=romega
Substituting this into the centripetal force formular
F= (m*romega*romega)/r
F=mrw^2
So using this
F=5 * 3 * 2π * 2π
F=60 * π^2N