An object with a mass of #5 kg# is revolving around a point at a distance of #3 m#. If the object is making revolutions at a frequency of #1 Hz#, what is the centripetal force acting on the object?

1 Answer
Jan 23, 2018

Answer:

#60π^2N#

Explanation:

#"Centripetal force" = (m*v^2)/r#
The frequency was given as 1hz
Then #"angular velocity" =2πf =(2π" rad")/s#
Remember that #"linear velocity" = "angular velocity"*"distance"#
#V=romega#
Substituting this into the centripetal force formular
#F= (m*romega*romega)/r#
#F=mrw^2#
So using this
#F=5 * 3 * 2π * 2π#
#F=60 * π^2N#