An object with a mass of #5 kg# is revolving around a point at a distance of #3 m#. If the object is making revolutions at a frequency of #8 Hz#, what is the centripetal force acting on the object?

1 Answer
Jan 6, 2016

Answer:

I found: #37,850.8N#

Explanation:

Centripetal force is:
#F_c=mv^2/r#
The time taken to complete a complete turn is the period or:
#T=1/("frequency")=1/8s#
The veoocity will be the circumference divided by the period or:
#v=(2pir)/T=(2*3.14*3)/(1/8)=150.7m/s#
So:
#F_c=5*(150.7)^2/3=37,850.8N#