An object with a mass of #5 kg# is revolving around a point at a distance of #3 m#. If the object is making revolutions at a frequency of #19 Hz#, what is the centripetal force acting on the object?

1 Answer
Jul 17, 2016

Answer:

I found #213kN#

Explanation:

You know that Centripetal Force is:
#F_C=mv^2/r#
Where
#v# is velocity;
#r# is the radius.
We need the velocity!
We can calculate it considering the length of the circumference decribed, i.e., #2pir# and divide it by the time #T# taken.
The time taken for a complete revolution, or period #T#, is given as:
#T=1/f=1/19s# where #f# is the frequency.
The velocity will then be:
#v=(2pir)/T=(2*pi*3)*19=358m/s#
So finally we have:
#F_C=mv^2/r=5(358)^2/3~~213kN#