An object with a mass of #5# #kg# is revolving around a point at a distance of #3# #m#. If the object is making revolutions at a frequency of #13# #Hz#, what is the centripetal force acting on the object?

1 Answer
Feb 14, 2016

Answer:

The centripetal force is given by #F=momega^2r# where #m# is the mass #(kg)#, #omega# is the frequency #(rads^-1)# and #r# is the radius #(m)#.

#F=momega^2r=5*94.25^2*3=133246# #N#

Explanation:

We need to convert the frequency: #15# #Hz=30pi=94.25# rads^-1#.