# An object with a mass of 5 kg is revolving around a point at a distance of 3 m. If the object is making revolutions at a frequency of 13 Hz, what is the centripetal force acting on the object?

Feb 14, 2016

The centripetal force is given by $F = m {\omega}^{2} r$ where $m$ is the mass $\left(k g\right)$, $\omega$ is the frequency $\left(r a {\mathrm{ds}}^{-} 1\right)$ and $r$ is the radius $\left(m\right)$.

$F = m {\omega}^{2} r = 5 \cdot {94.25}^{2} \cdot 3 = 133246$ $N$

#### Explanation:

We need to convert the frequency: $15$ $H z = 30 \pi = 94.25$ rads^-1#.