An object with a mass of #6 kg# is on a surface with a kinetic friction coefficient of # 8 #. How much force is necessary to accelerate the object horizontally at # 9 m/s^2#?

1 Answer
Feb 20, 2016

Answer:

#F=524,88N#

Explanation:

#F_f=u_k*m*g" Friction Force"#
#F_n=F-F_f" Net Force"#
#F_n=m*a#
#F-F_f=m*a#
#F-u_k.m*g=m*a#
#u_k=8 ; a=9 m/s^2 ; m=6 kg#
#F-8*6*9,81=6*9#
#F=54+8*6*9,81#
#F=524,88N#