# An object with a mass of 6 kg is on a surface with a kinetic friction coefficient of  8 . How much force is necessary to accelerate the object horizontally at  9 m/s^2?

Feb 20, 2016

$F = 524 , 88 N$

#### Explanation:

${F}_{f} = {u}_{k} \cdot m \cdot g \text{ Friction Force}$
${F}_{n} = F - {F}_{f} \text{ Net Force}$
${F}_{n} = m \cdot a$
$F - {F}_{f} = m \cdot a$
$F - {u}_{k} . m \cdot g = m \cdot a$
u_k=8 ; a=9 m/s^2 ; m=6 kg
$F - 8 \cdot 6 \cdot 9 , 81 = 6 \cdot 9$
$F = 54 + 8 \cdot 6 \cdot 9 , 81$
$F = 524 , 88 N$